Magic Square Photo
Magicsquire Photoshop

Mar 18, 2011 Adobe

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I'm designing a 3 x 3 Magic Square, where the 3 x 3 tables are made of up three adjacent list boxes. Upon starting the program, the 3 x 3 square consists only of the character '?' to represent a variable that has yet to be defined. The user will input through text boxes and button presses the characters 1 to 9, replacing the highlighted undefined '?' with the desired number. I'm required to include a Function procedure that can, at any time scan the 3x3 table and return an integer value of -1 if an undefined character '?' is present, a value of 0 if the rows, columns and diagonals do not sum to the same value, or the sum common to all rows columns and diagonals.
To start with I defined a 2D array and undefined.
Dim mSquare(2,2) As String
Dim undefined As String = '?'
Then I used a Sub to set the 3x3 table as undefined which I did not show to save space. Next I used a Sub to update the highlighted characters, allowing only one list box to be selected at a time and which I hope also assigns the the values to the array as they are updated. I removed parts of the code so this post isn't too big.
If lstCol2.SelectedIndex = -1 And lstCol3.SelectedIndex = -1 Then
lstCol1.Items(lstCol1.SelectedIndex) = input
txtInput.Text = '
End If
For i As Integer = 0 To 2
[Code] ...
What I'm stuck on is the Function design. I'm trying to design something to scan the array, and give back an integer depending on the results, which are to return an integer value of -1 if an undefined character '?' is present, a value of 0 if the rows, columns and diagonals do not sum to the same value, or the sum common to all rows columns and diagonals.
I'm currently trying
Function checkSquare(ByRef mSquare As String) As String
For i As Integer = 0 To 2
[Code] ...
At the moment I keep getting the error 'Public Readonly Default Property Chars(index As Integer) As Char'. I keep getting an error like this even using a single variable and defining each j individually, and I'm wondering if its possible to pass arrays to functions or do I need to do something else. Is what I'm trying to do even possible? I did a longer method in which I just check all the entries individually but I'm hoping there is a more efficient way. Its my plan B for now.

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Size:

Magic Square Photo

Explanation:

The numbers in the Red Squares form the 3x3 magic Square. The numbers beside the Red Squares show the totals for each row. The horizontal and vertical totals are to the right and below in green squares. The other, blue, squares show the diagonal totals - including all of the 'broken diagonals'. You can make your own Magic Square in two ways. Try both methods:

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Enter your own numbers into the Red Squares and then click on 'Add Rows'. You can experiment with any numbers using any strategy.
Put numbers in the top set of squares and click on 'Make Square'. If you try this method try any numbers you like. But, to get a conventional square use:
- Numbers 6, 3, and 0 in one row -try changing the order.
- Numbers 2, 1, 0, and 1 in the other row.

How does this Work?:

Positioning your Mouse over a Blue Arrow distributes the pattern of components in the Magic Square. This reveals the underlying structure of a 3x3 Magic Square. Actually, all 3x3 Magic Squares have an identical structure. And, if the same numbers are used, e.g., 1 to 9, the same square always results; it may be reflected, rotated, or both, but it is always the same square.

In the 3x3 square, it is impossible to make all of the diagonals 'magic'. The Main Diagonals are 'Magic' when you put the middle value (the '3' and the '1') in the center location in their sequences in the top array. If you put these 'middle' numbers in other positions, then one of the broken diagonals becomes magic instead.

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Mar 6, 2010

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